Possible Duplicate:
Pattern consisting of numbers moving in clockwise direction around a rectangular shape (length and breadth decreasing each time)
How to print a 2 dimensional array in spiral order using JAVA? Please help, I don't have any idea.
sample array:
1 2 3 4
5 6 7 8
9 10 11 12
13 14 15 16
output:
1 2 3 4 8 12 16 15 14 13 9 5 6 7 11 10
here is what i tried:
public static void main(String[] args) {
int[][] values = {{1,2,3,4}, {5,6,7,8}, {9,10,11,12}, {13,14,15,16}};
for (int i = (values.length * values[0].length)-1, j = 0; i > 0; i--, j++) {
for (int k = j; k < i; k++) {
System.out.print(values[j][k]);
}
for (int k = j; k < i; k++) {
System.out.print(values[k][i]);
}
for (int k = i; k > j; k--) {
System.out.print(values[i][k]);
}
for (int k = i; k > j; k--) {
System.out.print(values[k][j]);
}
}
}
here is some Java solution:
public static final int X_SIZE = 4;
public static final int Y_SIZE = 4;
public static void main(String[] args) {
int[][] array = new int[X_SIZE][Y_SIZE];
for(int i = 0; i < X_SIZE; i++){
for (int j = 0; j < Y_SIZE; j++){
array[i][j] = i * X_SIZE + (j + 1);
System.out.print(array[i][j] + " ");
}
System.out.println();
}
System.out.println("************");
System.out.println("Spiral");
spiralPrint(X_SIZE, Y_SIZE, array);
}
public static void spiralPrint(int xSize, int ySize, int matrix[][]){
int i, k = 0, l = 0;
xSize--; ySize--;
while(k <= xSize && l <= ySize){
for(i = l; i <= ySize; ++i) {
System.out.print(matrix[k][i]+ " ");
}
k++;
for(i = k; i <= xSize; ++i) {
System.out.print(matrix[i][ySize] + " ");
}
ySize--;
for(i = ySize; i >= l; --i) {
System.out.print(matrix[xSize][i] + " ");
}
xSize--;
for(i = xSize; i >= k; --i) {
System.out.print(matrix[i][l] + " ");
}
l++;
}
}