Inspired from https://perlmaven.com/datetime, I am attempting to find the number of hours of difference between 2024-01-03T19:00:00 and 2024-01-07T16:00:00 (93 hours).
#!/usr/bin/env perl
use 5.038;
use warnings FATAL => 'all';
use autodie ':default';
use DDP;
use Devel::Confess 'color';
use DateTime;
sub str_to_date ($date) {
if ($date =~ m/^(\d+) # year
\-(\d{1,2}) # month
\-(\d{1,2}) # day
T
(\d+) # hour
:
(\d+) # minutes
:
(\d+) # seconds
/x) {
return DateTime -> new(
year => $1,
month => $2,
day => $3,
hour => $4,
minute=> $5,
second=> $6,
);
} else {
die "$date failed regex.";
}
} # later dates are "greater"
my $wed_date = str_to_date('2024-01-03T19:00:00');
say $wed_date->day;
my $sun_date = str_to_date('2024-01-07T16:00:00');
my $diff = $sun_date - $wed_date; # returns a duration object
p $diff;
say $diff->clock_duration->in_units('hours'); # 21, but should be 93
say $diff->in_units('hours'); # 21 again
say $diff->hours; # 21 again
say $sun_date->delta_days($wed_date)->in_units('hours'); # 0
p $diff->deltas;
all of the methods that I have found from https://metacpan.org/pod/DateTime::Format::Duration are giving incorrect answers.
Alternatively, if I remove the parsing,
#!/usr/bin/env perl
use 5.038;
use warnings FATAL => 'all';
use autodie ':default';
use DDP;
use Devel::Confess 'color';
use DateTime;
my $wed_date = DateTime->new(
year => 2024,
month=>1,
day=>3,
hour=>19
);#str_to_date('2024-01-03T19:00:00');
my $sun_date = DateTime->new(
year=>2024,
month=>1,
day=>7,
hour=>16#my $sun_date = str_to_date('2024-01-07T16:00:00');
);#
say $wed_date->day;
my $diff = $sun_date - $wed_date;
p $diff;
say $diff->clock_duration->in_units('hours'); # 21, but should be 93
say $diff->in_units('hours'); # 21 again
say $diff->hours; # 21 again
say $sun_date->delta_days($wed_date)->in_units('hours'); # 0
p $diff->deltas; # 10
the answers are identical.
the DateTime::Duration object appears to be ignoring the days in between, and only focusing on the difference between the hours.
How can I get the correct # of hours between two dates?
Use ->delta_ms
instead of ->subtract_datetime
(the method invoked by subtraction).
A duration measured in days can't be converted into hours, since not all days have the same number of hours. In fact, only these conversions are safe:
As such, ->in_units( 'hours' )
only converts the hour and minute components of the duration into hours.
$sun_date - $wed_date
returns a duration of 3 days and 1260 minutes.
->in_units( 'hours' )
returns int( 0 + 1260/60 ) = 21 hours.
The solution is to create a duration that consists of hours and/or minutes instead of days.
$sun_date->delta_ms( $wed_date )
returns a duration of 5580 minutes.
->in_units( 'hours' )
returns int( 0 + 5580/60 ) = 93 hours.