I am implementing a queue. I have a Vec
class that looks like this:
#include <cstddef>
#include <span>
template<typename T, size_t Extent, bool Dynamic = (Extent == std::dynamic_extent)>
class Vec {
public:
constexpr size_t capacity(void) const;
~Vec();
};
template<typename T, size_t Extent>
class Vec<T, Extent, true> {
// Dynamic version
public:
Vec(size_t capacity);
};
template<typename T, size_t Extent>
class Vec<T, Extent, false> {
// Statically-sized version of the class
public:
constexpr Vec() = default;
};
In other words, Vec
can be constructed with constexpr Vec()
when Extent != std::dyanmic_extent. Otherwise, a size must be passed in, and the constructor is Vec(size_t capacity)
. This is designed to be similar to the api provided by std::span.
How can I include this in a new class, Queue
, such that I can have the majority of functionality be shared between the two classes, but still have specialized ctors. For example, I want to write this:
template<typename T, size_t Extent = std::dynamic_extent>
class Queue {
public:
template</* only enable if Extent != std::dynamic_extent */>
constexpr Queue() {}
template</* only enable if Extent == std::dynamic_extent */>
Queue(size_t size) : m_slots(size) {}
// Other methods...
private:
Vec<T, Extent> m_slots;
// Other fields ...
};
I am aware, I could add a bool Dynamic
parameter matches Vec<T>
, but then I would need repeat all of the fields in each class, and provide duplicate function definitions.
I have tried a few different variants of template expressions (only templates for constexpr Queue()
are shown, expressions for Queue(size_t size)
are just the obvious inverses).
template<typename = typename std::enable_if_t<Extent != std::dynamic_extent>>
constexpr Queue() {}
std::enable_if
template<std::enable_if_t<Extent != std::dynamic_extent, bool> = true>
Both of these attempts failed to compile, with the warning:
/usr/bin/../lib/gcc/x86_64-linux-gnu/12/../../../../include/c++/12/type_traits:2608:44: error: no type named 'type' in 'std::enable_if<false, bool>'; 'enable_if' cannot be used to disable this declaration
2608 | using enable_if_t = typename enable_if<_Cond, _Tp>::type;
| ^~~~~
../src/queues/spsc.hh:34:16: note: in instantiation of template type alias 'enable_if_t' requested here
34 | template<std::enable_if_t<Extent == std::dynamic_extent, bool> = true>
|
How can I implement this behavior? Is there a better pattern that I'm not seeing?
I've reproduced the issue, with both of my attempts, in this godbolt.
If you look at cppreference's documentation for std::span
's constructor, you will see how it uses std::dynamic_extent
in C++20 to limit some of its constructors. FYI, it's not using SFINAE in a template parameter at all, it uses the new explicit(expression)
feature instead, eg:
constexpr span() noexcept; template< class It > explicit(extent != std::dynamic_extent) constexpr span( It first, size_type count ); template< class It, class End > explicit(extent != std::dynamic_extent) constexpr span( It first, End last ); template< std::size_t N > constexpr span( std::type_identity_t<element_type> (&arr)[N] ) noexcept; template< class U, std::size_t N > constexpr span( std::array<U, N>& arr ) noexcept; template< class U, std::size_t N > constexpr span( const std::array<U, N>& arr ) noexcept; template< class R > explicit(extent != std::dynamic_extent) constexpr span( R&& range ); template< class U, std::size_t N > explicit(extent != std::dynamic_extent && N == std::dynamic_extent) constexpr span( const std::span<U, N>& source ) noexcept; constexpr span( const span& other ) noexcept = default;