Continuing while loop after catching an InputMissMatchException, Java

Question

I'm new in Java and have a problem after catching an exception. After catching an exception the program ends, but i want to continue the loop. The use of the program is that a user type in numbers between 1 and 10 through a scanner until the typed number is equal to the random number defined before.

public class GuessingGame {

    public static void main(String[] args) {

        System.out.println("Welcome!");

        int min = 1;
        int max = 1000;

        int randomNumber = (int) (Math.random() * (max - min) + 1) + min;

        Scanner scanner = new Scanner(System.in);

        int firstDraw = 1;
        int maxDraw = 1000;

        try {

            while (firstDraw < maxDraw) {

                System.out.println("Please enter your guess: ");

                int guessingNumber = scanner.nextInt();

                if (guessingNumber < randomNumber) {
                    System.out.println("Too small!");
                } else if (guessingNumber > randomNumber) {
                    System.out.println("Too big!");
                } else {
                    System.out.println("You win");
                }
                firstDraw++;
            }
        } catch (InputMismatchException e){
            System.out.println("Not a number - try again!");
        }
    }
}

I guess the problem is, where im going to place the try-catch block. I tried several possibilities but i dont get the right solution. If I just type in numbers, the program works and it ends until i guessed the right number. But if i use letters instead of numbers, it ends the program. I also saw some similiar problems asked before but i really don't get it

Thy for your help fellows :)

Answer 1

"... After catching an exception the program ends, but i want to continue the loop. ..."

Use the Scanner#next, and Integer#parseInt, methods.
And, place the try-catch within the loop.

Additionally, when the correct value is guessed, break the loop.

Note that the parseInt method throws a NumberFormatException, and not a InputMismatchException.

while (firstDraw < maxDraw) {

    System.out.println("Please enter your guess: ");

    try {
        int guessingNumber = Integer.parseInt(scanner.next());

        if (guessingNumber < randomNumber) {
            System.out.println("Too small!");
        } else if (guessingNumber > randomNumber) {
            System.out.println("Too big!");
        } else {
            System.out.println("You win");
            break;
        }
        firstDraw++;
    } catch (NumberFormatException e){
        System.out.println("Not a number - try again!");
    }
}

Output

Welcome!
Please enter your guess: 
abc
Not a number - try again!
Please enter your guess: 
123
Too small!
Please enter your guess: 
456
Too big!
Please enter your guess: 
241
You win

On a final note, you can utilize the RandomGenerator#nextInt method, to specify a bounds.

int randomNumber = new Random().nextInt(min, max + 1);