I have a binary function:
public Integer binaryFunction(Integer a, Integer b){
//some stuff
}
And I have this stream:
Integer fixedValue = ...
List<Integer> otherValues = ...
otherValues.map(value -> binaryFunction(value, fixedValue)).collect(...);
I would like to know how can I use map(this::binaryFunction)
in my stream. I tried something like this but it won't work:
values.map(value -> (value, fixedValue)).map(this::binaryFunction).collect(...);
But it does not work. I'm looking for a supplier that can take two values.
Note: I don't want to change binaryFunction
declaration.
You can't do this. You must use the lambda you have shown.
You could write a function that modifies binary functions to fix their first argument, but its body is just going to be the same lambda.