I've used a few tutorials on OOP in JavaScript. It seemed to go well, until I met the following...
Result of expression 'this.prepareFrame' [undefined] is not a function.
Ok. I'm using prototype
and make use of the this
keyword.
See my app.js
page here...
// Plain "main" function called by the html page, like <script>main()</script>. This works nicely:
function main() {
engine = new AbstractEngine();
engine.init();
}
// Next creates a new instance of my AbstractEngine class. Seems to work so far:
function AbstractEngine() {}
// The init() method we called is defined afterwards:
AbstractEngine.prototype.init = function() {
this.initLoop();
}
// remark: I'm using "this", and according to the debugger, "this" refers to the AbstractEngine we made an instance of.
// Next, we define the initLoop method:
AbstractEngine.prototype.initLoop = function() {
setInterval(this.tick, 1000 / 30);
}
// Fine, everything works fine so far. Now get to define the "tick" method:
AbstractEngine.prototype.tick = function() {
this.prepareFrame();
this.update();
}
// Ok, we're in trouble. The error message is output to the console and I don't understand why... The prepareFrame() and update() methods are defined right afterwards:
AbstractEngine.prototype.update = function() {
console.log('updating!');
}
AbstractEngine.prototype.prepareFrame = function() {
console.log('preparing frame');
}
// I read my code twice, but didn't find beginner's mistakes like typo or whatever. But well, cosnider I'm a beginner
This:
setInterval(this.tick, 1000 / 30);
Should be:
var that = this;
setInterval(function () { that.tick(); }, 1000 / 30);
or alternately:
setInterval(this.tick.bind(this), 1000 / 30);
Explanation: when you pass simply this.tick
, that is the same as doing the following:
var temp = this.tick;
setInterval(temp, 1000 / 30);
But now, when temp
is called, JavaScript doesn't know what the this
pointer should be; that information gets lost, and it ends up getting bound to the global object (window
), or to null
if you are in strict mode.
So you need to somehow ensure that this.tick
is called as a method with the appropriate this
pointer. There are two ways to do this:
var that = this
, you can properly call that.tick
as a method on the original this
pointer.bind()
ing the this.tick
function to this
, you ensure it is called as a method with the appropriate this
every time: in other words, you could even do var temp = this.tick.bind(this)
and setInterval(temp, 1000 / 30)
.Note that bind
is not available in older browsers (notably IE <= 8 and all Safaris so far up to and including 5.1), in which case you'd need something like es5-shim.