I am trying simply to list all jobs under a folder
(not view) with the python-jenkins package.
I have a structure, say, https://jenkins.xxx.com/job/lvl1/job/lvl2/job/lvl3/
..
lvl2
?lvl3
?How the folder entity is presented in the python-jenkins package?
The answer to this is to separate the jobs with a slash. So, if the path in Jenkins is: parent/job/child1/job/child2
, you would use server.get_job_info('parent/child1/child2')
and the library will convert this to the proper path.