Is there a method to check if two arrays contain same element in any order and check if same element is obtained with same index in ruby?

Question

arr = [1,4,6,3]
arr2 = [3,4,3,6]

arr.each do |item|
 p "X" if arr2.include?(item)
end

but the above only returns X if the element is found but I want it to return "O" when both array contain same element in the same index and I don't want the X to repeat if there is more than one element found.

I tried using eachwithindex but couldn't get the result

Answer 1

I would wrap the logic into a class with a few helper methods:

class CodeBreaker
  def initialize(guess, code)
    @guess = guess
    @code = code
    @numbers = Set.new(code)

    return if guess.size == code.size

    raise ArgumentError, 'guess and code need to share the same size'
  end

  def hint 
    guess.map.with_index do |number, index|
      mark_when_equal_at_index(index) || mark_when_number_in_code(number) || '-'
    end
  end

  private

  attr_reader :guess, :code, :numbers

  def mark_when_equal_at_index(index)
    'O' if guess[index] == code[index]
  end

  def mark_when_number_in_code(number)
    'X' if code.include?(number)
  end
end

code_breaker = CodeBreaker.new([1, 4, 6, 3], [3, 4, 3, 6])
code_breaker.hint
#=> ["-", "O", "X", "X"]