Chrome Extension Question: How to open popup_1.html if a statement is true, else open popup_2.html if a statement is false?

Question

I'm new in developing Chrome Extensions and a beginner in JavaScript. I need help in my chrome extension project.

Either if/else or a switch statement would be okay. I can't find a solution so far. I need my popup to show popup_1.html if the condition is true, and if it is false, then use popup_2.html

Answer 1

First, Set html file by setPopup method
then open popup by openPopup(); method

const condition = true;
chrome.action.setPopup({ popup:condition ?  "popup_1.html": "popup_2.html"  });
chrome.action.openPopup();