Is there a cipher method that uses 9 digit(starts with 8,9 or else) and 10 digit(only starts with 1)

Question

1752462448 1933193007 1667526190 1684632419 1869767777 1886400099 1869426529 1953784163 1751999854 1953705777 808924214 943272760 825768241 858992688 876162865 808924214 959918133 892810033 825832761 808726350 1162236485 1412330081 1912602624 there is the cipher.

i tried dcode.fr Cipher Identifier and it says this is base36. yes i found something with it like a another cipher. i tried to decode it too but got nothing.

Answer 1

Example in Python for its universal intelligibility:

c = '1752462448 1933193007 1667526190 1684632419 1869767777 1886400099 1869426529 1953784163 1751999854 1953705777 808924214 943272760 825768241 858992688 876162865 808924214 959918133 892810033 825832761 808726350 1162236485 1412330081 1912602624'
b = [bytes.fromhex(
        f'{int(a):08x}').decode() for a in c.split()]
print(''.join(b).rstrip('\x00'))

https://cdn.discordapp.com/attachments/1074689381891330049/1074697055731195904/NEFRET.rar

Note that b is the following list (with the last element 'r\x00\x00\x00'):

['http', 's://', 'cdn.', 'disc', 'orda', 'pp.c', 'om/a', 'ttac', 'hmen', 'ts/1', '0746', '8938', '1891', '3300', '49/1', '0746', '9705', '5731', '1959', '04/N', 'EFRE', 'T.ra', 'r\x00\x00\x00']

Therefore, wee need to remove all trailing ␀ (U+0000, Null) characters (see .rstrip('\x00') in the last line of above code snippet).