i have this array
i want to store it on new array groupped by date and shift with new column totale of shifts per date
const arr = [
{ sum: 77, shift: 1, date: "2020-07-05T00:00:00" },
{ sum: 25, shift: 2, date: "2020-07-05T00:00:00" },
{ sum: 05, shift: 2, date: "2020-07-05T00:00:00" },
{ sum: 15, shift: 2, date: "2020-07-05T00:00:00" },
{ sum: 10, shift: 3, date: "2020-07-05T00:00:00" },
{ sum: 13, shift: 1, date: "2020-07-06T00:00:00" },
{ sum: 66, shift: 2, date: "2020-07-06T00:00:00" },
{ sum: 30, shift: 3, date: "2020-07-06T00:00:00" },
{ sum: 50, shift: 1, date: "2020-07-07T00:00:00" },
{ sum: 40, shift: 2, date: "2020-07-07T00:00:00" },
];
i already calculed totals but i dont know how to groupe by date and shift
i want an output like this
date | shift 1 | shift 2 | shift 3 | totale |
---|---|---|---|---|
07-05-2020 | 77 | 45 | 10 | 132 |
07-06-2020 | 13 | 66 | 30 | 109 |
07-07-2020 | 50 | 40 | 90 |
i tried this but not returning the correct values
const grouped = arr.reduce((acc, { sum, shift, date }) => {
let dateKey = date.slice(0, 10);
acc[dateKey] = acc[dateKey] || {};
acc[dateKey][`Shift${shift}`] = sum;
acc[dateKey].total = (acc[dateKey].total || 0) + sum;
return acc;
}, {});
I think this function is what you need.
const computeArray = (arr) => {
const result = {}
arr.forEach(item => {
const field = `shift${item.shift}`
if(!result[item.date]) {
result[item.date] = {}
}
result[item.date][field] = (result[item.date][field] || 0) + item.sum
result[item.date].total = (result[item.date].total || 0) + item.sum
})
return Object.keys(result).map(key => ({
date: key,
...result[key]
}))
}