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javadoubleinfinity

double d=1/0.0 vs double d=1/0

double d=1/0.0;
    System.out.println(d);

It prints Infinity , but if we will write double d=1/0; and print it we'll get this exception: Exception in thread "main" java.lang.ArithmeticException: / by zero at D.main(D.java:3) Why does Java know in one case that diving by zero is infinity but for the int 0 it is not defined? In both cases d is double and in both cases the result is infinity.

Solution

  • Floating point data types have a special value reserved to represent infinity, integer values do not.

    In your code 1/0 is an integer division that, of course, fails. However, 1/0.0 is a floating point division and so results in Infinity.