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javascriptzod

What is the difference between z.optional(z.string()) and z.ostring() of zod?

To make any schema optional, I've seen that zod provides two methods: z.optional(z.string()) and z.ostring(). I wonder what is the difference between them? And what should I use for most cases?

Solution

  • Looking at the source code reveals that:

    const ostring = () => stringType().optional();

    And from the readme we know that:

    const optionalString = z.string().optional(); // string | undefined

// equivalent to
z.optional(z.string());

    So there is no difference