Remove optional for [String : Any] dictionary keys

Question

I have an dictionary like this:

[
    "Optional(Optional(\"Optional(Optional(\\\"Optional(Optional(\\\\\\\"Optional(Optional(257))\\\\\\\"))\\\"))\"))": "Seçenek 2",
    "Optional(Optional(\"Optional(Optional(\\\"Optional(Optional(\\\\\\\"Optional(Optional(261))\\\\\\\"))\\\"))\"))": "55"
]

How remove "Optional" for all keys and use Int values like this:

["57": "Seçenek 2", "61": "55"]

Answer 1

It is awkward to me answer this question, the below code will provides the your requirement

var dictionary = [
    "Optional(Optional(\"Optional(Optional(\\\"Optional(Optional(\\\\\\\"Optional(Optional(257))\\\\\\\"))\\\"))\"))": "Seçenek 2",
    "Optional(Optional(\"Optional(Optional(\\\"Optional(Optional(\\\\\\\"Optional(Optional(261))\\\\\\\"))\\\"))\"))": "55"
]

for (key, value) in dictionary{
    let lKey = key.replacingOccurrences(of: "Optional(", with: "").replacingOccurrences(of: "\"", with: "").replacingOccurrences(of: ")", with: "").replacingOccurrences(of: "\\", with: "")
    dictionary.removeValue(forKey: key)
    dictionary[lKey] = value
}

print(dictionary)
//Output: ["261": "55", "257": "Seçenek 2"]

Suggention

I suggest you to handle the key value before creating your dictionary. User if let to unwrap the key and then add key value pair to your dictionary