Dynamically populate a subarray inside of an array declaration

Question

I'm trying to create an array inside an array, using a for loop - here's my code:

array(
    'label' => 'Assign to user',
    'desc' => 'Choose a user',
    'id' => $prefix . 'client',
    'type' => 'radio'
    'options' => array( 
        foreach ($clients as $user) {
         $user->user_login => array (  
            'label' => $user->user_login,  
            'value' => $user->user_login,
            ), 
        }
    )
)

Unfortunately this gives me a

"Parse error: syntax error, unexpected T_CONSTANT_ENCAPSED_STRING, expecting ')'"

For the line:

'options' => array( 

I'm at a bit of a loss as to what has gone wrong. $clients is defined elsewhere, so that is not the problem.

Answer 1

That's invalid syntax. You'd have to build the "parent" portions of the array first. THEN add in the sub-array stuff with the foreach loop:

$foo = array(
    'label' => 'Assign to user',
    'desc' => 'Choose a user',
    'id' => $prefix.'client',
    'type' => 'radio',
    'options' => array()
);

foreach ($clients as $user) {
    $foo['options'][] = array (  
        'label' => $user->user_login,  
        'value' => $user->user_login,
    );
}