I've been on this for a while but haven't been able to arrive at my desired result. I'd like to compare items in two arrays based on their indexes. Something like this:
const first = 0;
const second = 1;
const result = []; // should equal (false, true, false)
const final = [[[2,3],[1,1]],[[4,2],[3,0]],[[0,3],[1,1]]];
for (let i = 0; i < final.length; i++) {
for (let j = 0; j < final[i].length; j++){
//Comparison between ((2 and 3) && (1 and 1)) with a single result.
//Should also compare between ((4 and 2) && (3 and 0)) and many other nested arrays
//This logic is not the right one as it can't do the comparison as intended.
if (final[i][j][first] > final[i][j][second]) {
result.push(true);
} else result.push(false);
}
I hope this is understood, enough. There is a very similar problem like this one. I don't know if it's right to post it here or open another ask a question, but they're both similar.
Thanks very much.
You can try it :
const first = 0;
const second = 1;
const final = [[[2,3],[1,1]],[[4,2],[3,0]],[[0,3],[1,1]]];
const result = final.map(([e1, e2]) => (e1[first] > e1[second] && e2[first] > e2[second]))
console.log(result)
// with non arrow function
function compareArr(arr, first, second) {
return arr.map(function (ele) {
return ele[0][first] > ele[0][second] && ele[1][first] > ele[1][second]
})
}
console.log(compareArr(final, first, second))
// with non map function :
function compareArr1(arr, first, second) {
let result1 = []
for(let i = 0; i < arr.length; i++) {
result1[i] = true
for(let j = 0; j < arr[i].length; j++) {
if(!(arr[i][j][first] > arr[i][j][second]))
result1[i] = false
}
}
return result1
}
console.log(compareArr1(final, first, second))
UPDATE : edit with suggest from @yes sir
Update : about ([e1,e2])
:
normal : Array.map((ele) => .....)
with structure of ele is [a, b]
It can use same as : Array.map(([a, b]) => .....)
Document of it : Destructuring assignment