Is it possible to define a custom cast on an object to become the result of a method call?

Question

Is it possible to define a custom cast on an object so that the objects casts to the result of a method call?

class Foo {
  public:
    ...
    int method() { return 3; }
};

Foo foo;
int bar = foo + 7; // 10

Answer 1

Agh. I was overthinking it.

#include <iostream>
#include <string>

class Foo {
    public:
    Foo() { _data = 3; }
    int method() { return _data; }
    operator int() {
        return method();
    }
    int _data;
};

int main()
{
  Foo foo;
  int bar = foo + 7;
  std::cout << bar << std::endl;
}