Trying to have fun with a twitter bot.
The idea is : according to the art institute of chicago API, posting a Tweet with the informations (Artist, Date, Place...) And the media (picture).
I can't upload a media here, bellow you can see the traceback that I am trying to fix.
I will appreciate ! B
import tweepy
import requests
import random
import time
import io
############################# My logs ######################################
def twitter_api():
consumer_key = 'xxxxxxxxxxxxxxxxxxxxxxxxxxxx'
consumer_secret = 'xxxxxxxxxxxxxxxxxxxxxxxxxxxx'
access_token = 'xxxxxxxxxxxxxxxxxxxxxxxxxxxx'
access_token_secret = 'xxxxxxxxxxxxxxxxxxxxxxxxxxxx'
auth = tweepy.OAuthHandler(consumer_key, consumer_secret)
auth.set_access_token(access_token, access_token_secret)
api = tweepy.API(auth)
return api
############################# My fonctions #################################
############################# The Loop ######################################
while True:
get_number()
r = requests.get(f"https://api.artic.edu/api/v1/artworks/{get_number()}")
a = r.json()
get_Titre(),get_Artist(),get_Date(),get_Place(),get_Im()
requests2 = (f"https://www.artic.edu/iiif/2/{get_Im()}/full/843,/0/default.jpg")
print("Imge ok:....................", requests2)
print(type(requests2))
message = (get_Titre()+ get_Artist()+str(get_Date())+get_Place())
print("La tête du tweet sera:", message)
twitter_api().update_status_with_media(message,requests2)
time.sleep(14400)
Here is the Traceback :
Traceback (most recent call last):
File "C:\PycharmProjects\TwitterBot\main.py", line 76, in <module>
twitter_api().update_status_with_media(message,requests2)
File "C:\PycharmProjects\TwitterBot\venv\lib\site-packages\tweepy\api.py", line 46, in wrapper
return method(*args, **kwargs)
File "C:\PycharmProjects\TwitterBot\venv\lib\site-packages\tweepy\api.py", line 1181, in update_status_with_media
files = {'media[]': stack.enter_context(open(filename, 'rb'))}
OSError: [Errno 22] Invalid argument: 'https://www.artic.edu/iiif/2/904ea189-c852-5f84-c614-a26a851f9b74/full/843,/0/default.jpg'
See documentation for update_status_with_media - second argument has to be filename.
update_status_with_media(text, filename, file, ...)
But third argument can be file-like object
and this means object which has function .read()
.
If you would use urllib.request
then it gives object which has .read()
and it works.
BTW: you have to use any text as second argument - can be fake filename but function needs it.
import os
import urllib.request
import tweepy
url = "https://www.iheartradio.ca/image/policy:1.15731844:1627581512/rick.jpg?f=default&$p$f=20c1bb3"
text = "Testing module tweepy"
# --- create file_like_object ---
file_like_object = urllib.request.urlopen(url)
# --- send tweet ---
consumer_key = os.getenv('TWITTER_CONSUMER_KEY')
consumer_secret = os.getenv('TWITTER_CONSUMER_SECRET')
access_token = os.getenv('TWITTER_ACCESS_TOKEN')
access_token_secret = os.getenv('TWITTER_ACCESS_TOKEN_SECRET')
auth = tweepy.OAuthHandler(consumer_key, consumer_secret)
auth.set_access_token(access_token, access_token_secret)
twitter_api = tweepy.API(auth)
# use any filename as second argument, and file-like object as third argument
twitter_api.update_status_with_media(text, 'fake_name.jpg', file=file_like_object)
With requests
you have to use io.BytesIO
to create file-like object
import os
import io
import requests
import tweepy
url = "https://www.iheartradio.ca/image/policy:1.15731844:1627581512/rick.jpg?f=default&$p$f=20c1bb3"
text = "Testing module tweepy"
# --- create file_like_object ---
response = requests.get(url)
file_like_object = io.BytesIO(response.content)
# --- send tweet ---
consumer_key = os.getenv('TWITTER_CONSUMER_KEY')
consumer_secret = os.getenv('TWITTER_CONSUMER_SECRET')
access_token = os.getenv('TWITTER_ACCESS_TOKEN')
access_token_secret = os.getenv('TWITTER_ACCESS_TOKEN_SECRET')
auth = tweepy.OAuthHandler(consumer_key, consumer_secret)
auth.set_access_token(access_token, access_token_secret)
twitter_api = tweepy.API(auth)
# use any filename as second argument, and file-like object as third argument
twitter_api.update_status_with_media(text, 'fake_name.jpg', file=file_like_object)
EDIT:
Eventually you can use stream=True
and then response.raw
gives file-like object
but this is not so popular.
# --- create file_like_object ---
response = requests.get(url, stream=True)
file_like_object = response.raw