I want to create a function to simplify a list/vector. I can do it in python:
i = [1, 2, 3, 4, 5]
f = [1.1, 2.2, 3.3, 4.4, 5.5]
s = ["one", "two", "three", "four", "five"]
def simplify(lst):
if len(lst) == 0:
return 0
tmp = lst[0]
for x in range(1, len(lst)):
tmp += lst[x]
print(tmp)
return tmp
simplify(i)
simplify(f)
simplify(s)
but for c++ I would have to write the same function for many variable types (long long, double, int, string, char).
My question is, can I do in c++ like I did in python? (creating a single function for multiple types)
My question is, can I do in c++ like I did in python? (creating a single function for multiple types)
Almost. A C++ function template is not a function, but using one can look indistinguishable from it.
You will also struggle with your choice of -1 as the result if the sequence is empty, as -1 is not a string.
template <typename Range>
std::ranges::range_value_t<Range> simplify(Range && range) {
auto it = std::ranges::begin(range);
if (it == std::ranges::end(range)) return -1; // this will fail for strings
auto result = *it++;
for (; it != std::ranges::end(range); ++it) {
result += *it;
}
std::cout << result; // I assume this is for testing the function?
return result;
}
If you make a different choice about what to do with an empty input, there is a function very similar to yours in the standard library:
template <typename Range>
std::ranges::range_value_t<Range> simplify(Range && range) {
std::ranges::range_value_t<Range> zero {}; // 0 for numbers, empty string for strings, etc.
return std::accumulate(std::ranges::begin(range), std::ranges::end(range), zero);
}
int main() {
std::vector<int> i {1, 2, 3, 4, 5};
std::vector<double> f {1.1, 2.2, 3.3, 4.4, 5.5};
std::vector<std::string> s {"one", "two", "three", "four", "five"};
std::cout << simplify(i);
std::cout << simplify(f);
std::cout << simplify(s);
}