How to make name of users uniques by adding number of occurrence?

Question

I've list of users:

const users = [
  {
    id: 1,
    name: "Leanne Graham",
    phone: "1-770-736-8031 x56442",
  },
  {
    id: 2,
    name: "Ervin Howell",
    phone: "010-692-6593 x09125",
  },
  {
    id: 3,
    name: "Leanne Graham",
    phone: "1-463-123-4447",
  },
  {
    id: 4,
    name: "Leanne Graham",
    phone: "493-170-9623 x156",
  },
  {
    id: 5,
    name: "Chelsey Dietrich",
    phone: "(254)954-1289",
  },
  {
    id: 6,
    name: "Mrs. Dennis Schulist",
    phone: "1-477-935-8478 x6430",
  },
  {
    id: 7,
    name: "Kurtis Weissnat",
    phone: "210.067.6132",
  },
  {
    id: 8,
    name: "Nicholas Runolfsdottir V",
    phone: "586.493.6943 x140",
  },
  {
    id: 9,
    name: "Glenna Reichert",
    phone: "(775)976-6794 x41206",
  },
  {
    id: 10,
    name: "Leanne Graham",
    phone: "024-648-3804",
  },
];
for (const user of users) {
  let countUserOccured = users.reduce(
    (acc, curr) => (acc += curr.name == user.name),
    0
  );
  if (countUserOccured - 1 != 0) {
    user.name += countUserOccured;
  }
  console.log(user);
}

And I want users name be unique. if the name e.g. "Leanne Graham" in that case repeated many times I want first one add to his name 1, second one his name 2...
I've tried this approach: but its order DESC(from greater number of occurrence to the lowest I want it in order ASCending.

for (const user of users) {
  let countUserOccured = users.reduce(
    (acc, curr) => (acc += curr.name == user.name),
    0
  );
  if (countUserOccured - 1 != 0) {
    user.name += countUserOccured;
  }
  console.log(user);
}

Answer 1

you can do that with objects and counting the value that you want.

const counts = {};
users.forEach((user) => {
  counts[user.name] = (counts[user.name] || 0) + 1;
});
console.log(counts)