C++ compile time ternary conditional

Question

Please, help me to figure out syntax of compile time ternary conditional in C++:

#include <iostream>
#include <type_traits>
int main(void)
{
 //const auto y = constexpr(std::is_null_pointer_v<decltype(nullptr)>) ? 777 : 888.8;
 const auto y = constexpr(std::is_null_pointer_v<decltype(nullptr)> ? 777 : 888.8);
 std::cout<<y<<std::endl;
}

Both of the options above give me error: expected primary-expression before ‘constexpr’ (gcc-11.2.0; compiled with g++ -std=c++17).

Thank you very much for your help!

Answer 1

Although one solution is provided while I program it, I suggest other solution: making your consteval tenary function template, As it can handle different type in it.

template<bool T,auto A, auto B>
consteval auto tenary() {
    if constexpr (T) {
        return A;
    }
    else {
        return B;
    }
}

#include <iostream>
#include <type_traits>
int main(void)
{
    const auto y = tenary<std::is_null_pointer_v<decltype(nullptr)>,777,888.8>();
    std::cout << y << std::endl;
}