I will be using the same macro 24 times, but the ranges will differ (but at a constant rate) every time. Therefore I thought it would be smart to write the references as a function in order to reduce the length of the code, and also make it easier to change.
Now it looks like this:
Sheets("Planned time").Select
Range("I15:NJ32").Select
Selection.Copy
Sheets("Diff").Select
Range("I9").Select
Selection.PasteSpecial Paste:=xlPasteValues, Operation:=xlNone, SkipBlanks _
:=False, Transpose:=False
But I would like it to be something like this:
Sheets("Planned time").Select
Range("I(15+171x):NJ(32+171x)").Select
Selection.Copy
Sheets("Diff").Select
Range("I(9+56x)").Select
Selection.PasteSpecial Paste:=xlPasteValues, Operation:=xlNone, SkipBlanks _
:=False, Transpose:=False
Where the macro loops 24 times, but for each loop, increase the value of x by 1. x would need to be 0 in the first iteration, and 23 in the last one (totalling 24 iterations).
I know the coding is probably far off, but I think it illustrates what I want to accomplish in a good way.
Any assistance would be greatly appreciated.
UPDATE: Solved
Dim x As Integer
For x = 0 To 23
Sheets("Planned time").Select
Range("I" & cstr(15+171*x) & ":NJ" & cstr(32+171*x)).Select
Selection.Copy
Sheets("Diff").Select
Range("I" & cstr(9+56*x)).Select
Selection.PasteSpecial Paste:=xlPasteValues, Operation:=xlNone, SkipBlanks _
:=False, Transpose:=False
Next x
You want to build a string expression that, when evaluated in VBA, will be a valid address:
Range("I" & cstr(15+171*x) & ":NJ" & cstr(32+171*x)).Select
I assume you know how to build a FOR loop.
You can also 'build' range references by using numeric cell(row, column) expressions:
Range(cell(15+171*x,10),cell(32+171*x,374)).select