how to to make sinon return non promise I do mock expect

Question

I am using sinon to mock a return for a function and here is my code:

  sandbox.mock(monitoring).expects('getHttpRequestDuration').resolves({
    startTimer: () => {}
  });

The problem here is the return is wrapped in a promise and the actual function is not using any await

 const end = httpRequestTimer.startTimer(); 

is there a way I can return only

     {
        startTimer: () => {}
      }

not wrapped in a promise?

Answer 1

resolves returns a promise. The equivalent method in sinon to return a value is .returns:

  sandbox.mock(monitoring).expects('getHttpRequestDuration').returns({
    startTimer: () => {}
  });

See stub.returns in our docs.