my_table :
Name | Value |
---|---|
item_1 | AB |
item_2 | 2 |
item_3 | B1 |
item_1 | CD |
item_1 | EF |
item_2 | 3 |
item_3 | B2 |
item_4 | ZZ |
required output:
item_1 | item_2 | item_3 | item_4 |
---|---|---|---|
AB | 2 | B1 | ZZ |
CD | 3 | B2 | NULL |
EF | NULL | NULL | NULL |
SQL query :
with item_1 as (select value from my_table where name = 'item_1'),
item_2 as (select value from my_table where name = 'item_2'),
item_3 as (select value from my_table where name = 'item_3'),
item_4 as (select value from my_table where name = 'item_4')
select item_1.value, item_2.value,item_3.value, item_4.value from item_1 cross join item_2 cross join item_3 cross join item_4;
If I am using pivot along with MAX aggregate function, the query will display only max values of the corresponding items instead of displaying all the values.
Is there any way to split a single column into multiple columns(using where condition as mentioned in the above query) without cross join.
Use ROW_NUMBER
and then PIVOT
:
SELECT item_1,
item_2,
item_3,
item_4
FROM (
SELECT t.*,
ROW_NUMBER() OVER (PARTITION BY name ORDER BY ROWNUM) AS rn
FROM table_name t
)
PIVOT (
MAX(value) FOR name IN (
'item_1' AS item_1,
'item_2' AS item_2,
'item_3' AS item_3,
'item_4' AS item_4
)
)
Which, for the sample data:
CREATE TABLE table_name (Name, Value) AS
SELECT 'item_1', 'AB' FROM DUAL UNION ALL
SELECT 'item_2', '2' FROM DUAL UNION ALL
SELECT 'item_3', 'B1' FROM DUAL UNION ALL
SELECT 'item_1', 'CD' FROM DUAL UNION ALL
SELECT 'item_1', 'EF' FROM DUAL UNION ALL
SELECT 'item_2', '3' FROM DUAL UNION ALL
SELECT 'item_3', 'B2' FROM DUAL UNION ALL
SELECT 'item_4', 'ZZ' FROM DUAL;
Outputs:
ITEM_1 ITEM_2 ITEM_3 ITEM_4 AB 2 B1 ZZ CD 3 B2 null EF null null null
db<>fiddle here