Passing Pulumi S3 Bucket ID to AWS Lambda as a parameter

Question

I would like to pass the S3 bucket ID as a parameter to AWS Lambda via Pulumi. However, Pulumi passes this parameter On Build, so I obtain an Object reference in Lambda instead of the S3 path.

My code looks like this

bucket = s3.Bucket(resource_name="bucket", acl="private")
lambda_func = lambda_.Function("Function",
                               role=lambda_role.arn,
                               package_type="Image",
                               image_uri=docker.image_name,
                               image_config={"commands": ["api/main.handler"]},
                               vpc_config={"subnet_ids": private_subnet_ids,
                                           "security_group_ids": [internet_access.id],
                                          },
                               environment=lambda_.FunctionEnvironmentArgs(
                                               variables={"STORE_PATH": f"s3://s{bucket.id}/api"})
                               )

According to Pulumi documentation:

Outputs that contain strings cannot be used directly in operations such as string concatenation.

So I've tried the recommended methods like:

bucket_url = Output.all(bucket.id).apply(lambda l: f"http://{l[0]}/")

Or

url = Output.concat("http://", bucket.id, "/")

Any help is welcomed. Thank you in advance to everyone.

Answer 1

The last method should work fine. Note that bucket.id is just the name of the bucket, you need to build S3 access URL with it, e.g.

url = Output.concat("https://", bucket.id, ".s3.us-west-2.amazonaws.com")
# or url = Output.concat("s3://", bucket.id)

If this still doesn't do what you want, you could export the value of the url to see how it's wrong (or post the result to your question).

export('url', url)