Working on an Advent of Code puzzle I had found myself defining a function to transpose matrices of integers:
fun transpose(xs: Array<Array<Int>>): Array<Array<Int>> {
val cols = xs[0].size // 3
val rows = xs.size // 2
var ys = Array(cols) { Array(rows) { 0 } }
for (i in 0..rows - 1) {
for (j in 0..cols - 1)
ys[j][i] = xs[i][j]
}
return ys
}
Turns out that in the following puzzle I also needed to transpose a matrix, but it wasn't a matrix of Int
s, so i tried to generalize. In Haskell I would have had something of type
transpose :: [[a]] -> [[a]]
and to replicate that in Kotlin I tried the following:
fun transpose(xs: Array<Array<Any>>): Array<Array<Any>> {
val cols = xs[0].size
val rows = xs.size
var ys = Array(cols) { Array(rows) { Any() } } // maybe this is the problem?
for (i in 0..rows - 1) {
for (j in 0..cols - 1)
ys[j][i] = xs[i][j]
}
return ys
}
This seems ok but it isn't. In fact, when I try calling it on the original matrix of integers I get Type mismatch: inferred type is Array<Array<Int>> but Array<Array<Any>> was expected
.
The thing is, I don't really understand this error message: I thought Any
was a supertype of anything else?
Googling around I thought I understood that I should use some sort of type constraint syntax (sorry, not sure it's called like that in Kotlin), thus changing the type to fun <T: Any> transpose(xs: Array<Array<T>>): Array<Array<T>>
, but then at the return line I get Type mismatch: inferred type is Array<Array<Any>> but Array<Array<T>> was expected
So my question is, how do I write a transpose
matrix that works on any 2-dimensional array?
As you pointed out yourself, the line Array(cols) { Array(rows) { Any() } }
creates an Array<Array<Any>>
, so if you use it in your generic function, you won't be able to return it when Array<Array<T>>
is expected.
Instead, you should make use of this lambda to directly provide the correct value for the correct index (instead of initializing to arbitrary values and replacing all of them):
inline fun <reified T> transpose(xs: Array<Array<T>>): Array<Array<T>> {
val cols = xs[0].size
val rows = xs.size
return Array(cols) { j ->
Array(rows) { i ->
xs[i][j]
}
}
}
I don't really understand this error message: I thought Any was a supertype of anything else?
This is because arrays in Kotlin are invariant in their element type. If you don't know about generic variance, it's about describing how the hierarchy of a generic type compares to the hierarchy of their type arguments.
For example, assume you have a type Foo<T>
. Now, the fact that Int
is a subtype of Any
doesn't necessarily imply that Foo<Int>
is a subtype of Foo<Any>
. You can look up the jargon, but essentially you have 3 possibilities here:
Foo
is covariant in its type argument T
if Foo<Int>
is a subtype of Foo<Any>
(Foo
types "vary the same way" as T
)Foo
is contravariant in its type argument T
if Foo<Int>
is a supertype of Foo<Any>
(Foo
types "vary the opposite way" compared to T
)Foo
is invariant in its type argument T
if none of the above can be saidArrays in Kotlin are invariant. Kotlin's read-only List
, however, is covariant in the type of its elements. This is why it's ok to assign a List<Int>
to a variable of type List<Any>
in Kotlin.