Does exist a way to verify with ArchUnit that any method doesn´t throw any exception?

Question

I would like to know if exist a way in ArchUnit to avoid that the signature of a method throws any checked exception.

Answer 1

You can access a code unit's declared exceptions via JavaMethod.getThrowsClause() (or JavaConstructor.getThrowsClause(), respectively).

The following rule using a custom condition forbids the declaration of any exceptions – you can easily adapt it to your needs if you want to exclude RuntimeExceptions:

@ArchTest
static ArchRule no_code_units_should_declare_exceptions = noCodeUnits()
    .should(new ArchCondition<JavaCodeUnit>("declare exceptions") {
       @Override
       public void check(JavaCodeUnit codeUnit, ConditionEvents events) {
         int nThrowsDeclarations = codeUnit.getThrowsClause().size();
         String message = String.format("%s has %d throws declarations in %s",
             codeUnit.getDescription(), nThrowsDeclarations, codeUnit.getSourceCodeLocation()
         );
         events.add(new SimpleConditionEvent(codeUnit, nThrowsDeclarations > 0, message));
       }
    });