Cron expression for specific days using cron-utils

Question

I am using cron-utils jar for generating cron expression like:

0 0 0 ? * 1,3,7 *

At 00:00:00am, on every Sunday, Tuesday and Saturday, every month

How can i create the 'days of week' expression so it will be list and not only one value?

Below is my code for above expression:

CronDefinition definition = CronDefinitionBuilder.instanceDefinitionFor(CronType.QUARTZ);
CronBuilder cronBuilder = CronBuilder.cron(definition)
            .withYear(always())
            .withMonth(always())
            .withDoM(questionMark())
            .withHour(on(0))
            .withMinute(on(0))
            .withSecond(on(0))
            .withDoW(on(???????);

Answer 1

You can use and() and you will be able to pass multiple days.

Example:

CronDefinition definition = CronDefinitionBuilder.instanceDefinitionFor(CronType.QUARTZ);
CronBuilder cronBuilder = CronBuilder.cron(definition)
            .withYear(always())
            .withMonth(always())
            .withDoM(questionMark())
            .withHour(on(0))
            .withMinute(on(0))
            .withSecond(on(0))
            .withDoW(on(1).and(on(3)).and(on(5)));