Cant remove vowels from an array using filter that has multiple conditional statements

Question

wordArr = ['a', 'g', 'e', 'f'];
wordArr = wordArr.filter(function(l){
            return l !== 'a' || l!== 'e'|| l!== 'i'|| l!== 'o' || l!== 'u'; 
       });

My result: my wordArr doesnt change

Desire output: ['g', f'];

it only works with one condition, if i only check for one vowel. How do i make this work for multiple conditions?

thank you in advanced.

Answer 1

Your conditions are incorrect. Consider just the following:

return l !== 'a' || l!== 'e'

If the string (inside l) is foo, the result is true since it's not 'a'.

If the string is 'a', the result is true since it's not 'e':

return l !== 'a' || l!== 'e'
return false || true
return true

If the string is 'e', the result is true since it's not 'a':

return l !== 'a' || l!== 'e'
return true || false
return true

You need &&s instead.

return l !== 'a' && l!== 'e'&& l!== 'i'&& l!== 'o' && l!== 'u'; 

Or, even better:

const wordArr = ['a', 'g', 'e', 'f'];
console.log(wordArr.filter(str => !/[aeiou]/.test(str)));