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luaobfuscation

Why does this remove all "%" lua

So I am working on this obfuscator and when I add my encoding algorithm after the first ")" it removes all "%" in the algorithm, how do I fix this?

Here is the way i do it:

newScript = newScript:gsub('%)', algorithm , 1)
Solution

  • I suggest reading the PIL regarding captures. The symbol % is a special character, therefore you need to escape it:

    newScript = newScript:gsub('%)', algorithm:gsub('%%', '%%%%'), 1)

    This replaces every % in your replacement string with %%, which will then become % when used as replacement in newScript.

    The PIL even clearly says:

    By the way, because of those changes, a `%´ in the replacement string must be escaped as "%%".