Java SimpleDateFormat can not parse date in "yyyy-MM-dd'T'HH:mm:ss.SSSSSSSSSX" format pattern

Question

I have simple code, which parses string into date.

new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSSSSSSSSX").parse("2021-06-28T07:09:30.463931900Z")

It parses this string into Sat Jul 03 18:01:41 CEST 2021, which is not valid.

When I remove from pattern 'SSSSSSSSSX', it starts working and returns: Mon Jun 28 07:09:30 CEST 2021.

Problem is that I need nanoseconds, so I can not just get rid of this.

I found many similar topics, but any of them dealt with such date format.

Answer 1

Use java.time:

You can parse this example String without any explicit pattern, keep the precision as desired and, if necessary, format those date and time values in a multitude of custom ways.

Here's a small example:

public static void main(String[] args) {
    // example String (of ISO format)
    String input = "2021-06-28T07:09:30.463931900Z";
    // parse it (using a standard format implicitly)
    OffsetDateTime odt = OffsetDateTime.parse(input);
    // print the result
    System.out.println(odt);
    
    // if you want a different output, define a formatter
    DateTimeFormatter dtf = DateTimeFormatter.ofPattern(
            // use a desired pattern
            "EEE MMM dd HH:mm:ss O uuuu",
            // and a desired locale (important for names)
            Locale.ENGLISH);
    // print that
    System.out.println(odt.format(dtf));
}

This code example produces the following output:

2021-06-28T07:09:30.463931900Z
Mon Jun 28 07:09:30 GMT 2021