I'm java beginner and it's first time to use thread.
class Counter2 {
private int value = 0;
public void increment() {
value++;
printCounter();
}
public void decrement() {
value--;
printCounter();
}
public void printCounter() {
System.out.println(value);
}
}
class MyThread3 extends Thread {
Counter2 sharedCounter;
public MyThread3(Counter2 c) {
this.sharedCounter = c;
}
public void run() {
int i = 0;
while (i <= 100) {
sharedCounter.increment();
sharedCounter.decrement();
try {
sleep((int) (Math.random() * 2));
} catch (InterruptedException e) {
}
// System.out.println(i);
i++;
}
}
}
public class MyTest {
public static void main(String[] args) {
Thread t1, t2;
Counter2 c = new Counter2();
t1 = new MyThread3(c);
t1.start();
t2 = new MyThread3(c);
t2.start();
}
}
This code has 2 threads and 1 Counter, which is shared between the threads. The threads just repeat plus 1, minus 1 to the counter value. So, if I guess, the result should be 0. Because initial value was 0 and the number of incremented and decremented are the same. But some times the last printing number is not the 0, but -1 or -2 etc. please explain why this is this.
The Answer by Ranwala is correct.
AtomicInteger
An alternative solution I prefer is the use of the Atomic…
classes. Specifically here, AtomicInteger
. This class is a thread-safe wrapper around an integer.
Change your member field from Counter2 sharedCounter;
to AtomicInteger sharedCounter;
. Then use the various methods on that class to increment, to decrement, and to interrogate for current value.
You can then discard your Counter2
class entirely.
Also, you should know that in modern Java, we rarely need to address the Thread
class directly. Instead we use the executors framework added to Java 5.
Define your tasks as either a Runnable
or Callable
. No need to extend from Thread
.
See tutorial by Oracle, and search existing posts here on Stack Overflow.