argument of type "void" is incompatible error

Question

hello and thanks in advance for supporting,

I'm trying to send a pointer to function which is type void and receive nothing.

it didn't work well so far.

here is my minimal code that have this problem:

void func::foo()
{
    return;
}

and the function which use it is:

void func::create_func(void(*wanted_func)())
{
    wanted_func();
}

the problem is when it called:

create_func(foo);

please advice, I hope i haven't asked something that is very silly

Answer 1

From what I understand, you'd like to pass a member method pointer to another member method. So you'll have to bind an object instance to the method that you want to pass. Have a look at std::bind (Reference)

Here is a minimal example which I believe does what you want:

#include <iostream>
#include <functional>

class Func {
 public:
    void foo() {
      std::cout << "called foo\n";
    }
    
    void create_func(std::function<void()> functor) {
        functor();
    }

};

int main() {
    Func f;
    f.create_func(std::bind(&Func::foo, f));
    return 0;
}