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javascriptloopsfor-loopconditional-statementstimedelta

Is there a way to redefine a "let" value when a certain condition becomes True?


Be gentle:

I'm new to Javascript and curious about how I would go about running a for loop [or suggest a different loop that would be more fitting] that redefines a "let" value after a condition in the loop becomes True. When the last "else if" condition becomes True, it would redefine the Value1 value by adding the const add_to to it, and then begin the first two condition checks again. Infinite loop?

I've provided an example of my current code below:

const fetch = require('node-fetch');
const api_url = 'https://an-api-i-am-using-that-returns-Value1.com'
let Value1 = 100;
const add_to = 10;

async function getTotal() {

    const response = await fetch(api_url);

    Number_Returned = await response.json();
    Number_Left = Value1 - Number_Returned
    Time_Left = Number_Left * 60;

    if (Number_Left > 0){
        console.log(Number_Left)

        var d = parseInt(Time_Left / (3600 * 24));
        console.log(d)

        nd = Time_Left % (24 * 3600);
        var h = parseInt(nd/3600);
        console.log(h)

        Time_Left %= 3600;
        var m = parseInt((Time_Left/60));
        console.log(m)

        const longEnUSFormatter = new Intl.DateTimeFormat('en-US', { dateStyle: 'full', timeStyle: 'long' });

        var date = new Date();
        date.setMinutes(date.getMinutes() + (d * 24 * 60) + (h * 60) + m);
        console.log(longEnUSFormatter.format(date))
    }
    else if (Number_Left == 0 && Value1 == Number_Returned) {
        console.log(Number_Left)

        d = "no";
        console.log(d)
        h = "no";
        console.log(h)
        m = "no";
        console.log(m)
        date = "Today";
        console.log(date)
    }
    else if (Number_Left < 0) {
        console.log(Number_Left)

        d = "didn't work";
        console.log(d)
        h = "didn't work";
        console.log(h)
        m = "didn't work";
        console.log(m)
        date = "didn't work";
        console.log(date)
        Value1 =+ add_to;
    }
}

async function begin(){
    console.log('calling');
    const result = await getTotal();
    console.log(Value1);
}

begin();

Currently, the script returns the following results after running (example results):

When (Number_Left > 0) is True:

calling
3
0
0
3
Tuesday, April 27, 2021 at 7:55:59 PM GMT+1

When (Number_Left == 0 && Value1 == Number_Returned) is True:

calling
0
no
no
no
Today
98273492

When (Number_Left < 0) is True:

calling
-7
didn't work
didn't work
didn't work
didn't work
10

To reiterate, once the last condition becomes True, I would like to add the const add_to to the let value Value1, beginning the (Number_Left > 0) and (Number_Left == 0 && Value1 == Number_Returned) condition checks again.

Let me know if I can be more specific about what I'm trying to accomplish. Thanks in advance.


Solution

  • In order to do what I needed this code to do, I had to rewrite it. It may not be the best coding, but it works for what I'm trying to accomplish:

    const api_url = 'https://an-api-i-am-using-that-returns-Value1.com';
    
        async function getTotal(){
            resp = await fetch(api_url);
            Number_Returned = await resp.text();
            return Number_Returned
        }
    
        async function checkValue1(){
            Value1 = 100;
            const add_to = 10;
            cur = await getTotal();
    
            if (Value1>=cur){
                return cur
            }
            else if (Value1<cur){
                Value1 = Value1 + add_to
                return cur
            }
        }
    
        async function calculateTotal(){
            const theValue1 = await checkValue1();
            const numDifference = 2880;
            let numLeft = (Value1 - numDifference) - theValue1;
            let timeDelta = numLeft * 60.097;
            return timeDelta
        }
    
        async function calcDate(){
            let timeLeft = await calculateTotal();
            let d = parseInt(timeLeft / (3600 * 24));
            document.getElementById('days').innerHTML = d;
            nd = timeLeft % (24 * 3600);
            let h = parseInt(nd/3600);
            document.getElementById('hours').innerHTML = h;
            timeLeft %= 3600;
            let m = parseInt((timeLeft/60));
            document.getElementById('mins').innerHTML = m;
            const longEnUSFormatter = new Intl.DateTimeFormat('en-US', { dateStyle: 'full', timeStyle: 'long' });
            let date = new Date();
            date.setMinutes(date.getMinutes() + (d * 24 * 60) + (h * 60) + m);
            document.getElementById('date').innerHTML = longEnUSFormatter.format(date);
    }
    
    calcDate();