How to get the sum for each row?

Question

I want to find and display the row number that has the maximum sum and display the row values and this is sample input/output:

The problem is every time the maximum sum is the third row how to solve these issues.

   int [][] scores = new int[4][3];

    for (int i=0; i<scores.length; i++)
    {
        System.out.print("Enter values for row "+i+": ");
        for (int j=0; j<scores[i].length;j++)
            scores[i][j] = kbd.nextInt();
    }
    
    int sum, sumMax, ii=0;
    for (int i=0; i<scores.length; i++)
    {
        sum =0; sumMax = 0; ii=0;
        for (int j=0; j<scores[i].length;j++)
        {
            sum += scores[i][j];
            if (sum>sumMax)
            {
                sumMax = sum;
                ii = i;
            }
        }
    }

    System.out.println("Row "+ii+" has the maximum sum");
    System.out.print("Row "+ii+" has the following values: ");
    for (int j = 0; j < 3; j++)
           System.out.print(scores[ii][j] + " ");

Answer 1

To print a specific row, you need one loop only

System.out.print("Row " + ii + " has the following values: ");
for (int j = 0; j < 3; j++)
    System.out.print(scores[ii][j] + " ");

Or with Arrays.toString

System.out.println("Row " + ii + " has the following values: " + Arrays.toString(scores[ii]));

---

Also your finding max code is wrong, as you reset ii and sumMax to 0 for each row, the max can only be the last line, you need to keep track of these 2 along the rows. Also use the if only after computing the row's sum, no need to test at every bow of every row

int sum, sumMax = Integer.MIN_VALUE, ii = 0;
for (int i = 0; i < scores.length; i++) {
    sum = 0;

    for (int j = 0; j < scores[i].length; j++) {
        sum += scores[i][j];
    }

    if (sum > sumMax) {
        sumMax = sum;
        ii = i;
    }
}