Print a string in console.log instead of a number

Question

I want to print the strings: "Fizz", "Buzz" and "FizzBuzz" in console.log instead of the number they refer to. The point is that until now I can get both number and string, but I don't know how to overcome the number value with the string. For example, the console.log of the code below should be 1 2 Fizz and not 1 2 3 Fizz.

//Define listNumber
var listNumber;

//Generate numers from 1 to 100
for (i = 1; i <= 100; i++) {
  listNumber = i;
  console.log(listNumber);

  if ((listNumber % 3 == 0) && (listNumber % 5 == 0)) {
    console.log('FizzBuzz');
  } else if (listNumber % 3 == 0) {
    console.log('Fizz');
  } else if (listNumber % 5 == 0) {
    console.log('Buzz');
  }

}

Answer 1

You log the initial value before you do your check. Simply move it to the end of the evaluation, so that if it's neither Fizz, Buzz or FizzBuzz it prints the actual number.

//Define listNumber
var listNumber;

//Generate numers from 1 to 100
for (i = 1; i <= 100; i++) {
  listNumber = i;


  if ((listNumber % 3 == 0) && (listNumber % 5 == 0)) {
    console.log('FizzBuzz');
  } else if (listNumber % 3 == 0) {
    console.log('Fizz');
  } else if (listNumber % 5 == 0) {
    console.log('Buzz');
  } else {
    console.log(listNumber);
  }

}