I am trying to create the response in JSON format from a string in Javalin. JSON object must be from a string, not from class.
public static void main(String[] args) {
Javalin app = Javalin.create().start(9000);
String jsonString = "{'test1':'value1','test2':{'id':0,'name':'testName'}}";
JsonObject jsonObject= JsonParser.parseString(jsonString).getAsJsonObject();
app.error(404, ctx -> ctx.json(jsonObject));
...
}
With the code above, I am getting a 500 server error.
If you are using Gson, then switch to using Jackson, when using Javalin methods such as ctx.json()
.
If you used Maven to import Javalin, and if you used the javalin-bundle
, then you will already have Jackson, for example:
<dependency>
<groupId>io.javalin</groupId>
<artifactId>javalin-bundle</artifactId>
<version>3.13.3</version>
</dependency>
If you only used javalin
and not javalin-bundle
then you will need to add Jackson yourself - for example:
<dependency>
<groupId>com.fasterxml.jackson.core</groupId>
<artifactId>jackson-databind</artifactId>
<version>2.12.2</version>
</dependency>
The following is the code from the question, but re-worked to use Jackson (and to use valid JSON):
import com.fasterxml.jackson.core.JsonProcessingException;
import com.fasterxml.jackson.databind.JsonNode;
import com.fasterxml.jackson.databind.ObjectMapper;
import io.javalin.Javalin;
public class App {
public static void main(String[] args) throws JsonProcessingException {
Javalin app = Javalin.create().start(9000);
String jsonString = "{\"test1\":\"value1\",\"test2\":{\"id\":0,\"name\":\"testName\"}}";
ObjectMapper objectMapper = new ObjectMapper();
JsonNode jsonNode = objectMapper.readTree(jsonString);
app.error(404, ctx -> ctx.json(jsonNode));
}
}