as the title says i'm trying to find the number of non-zero pixels in a certain area of a cv::Mat, namely within a RotatedRect.
For a regular Rect one could simply use countNonZeroPixels on a ROI. However ROIs can only be regular (non rotated) rectangles.
Another idea was to draw the rotated rectangle and use that as a mask. However openCV neither supports the drawing of rotated rectangles nor does countNonZeroPixels accept a mask.
Does anyone have a solution for how to elegantly solve this ?
Thank you !
Ok, so here's my first take at it.
The idea is to rotate the image reverse to the rectangle's rotation and than apply a roi on the straightened rectangle.
You can probably speed this up by applying another roi before rotation to avoid having to rotate the whole image...
#include <highgui.h>
#include <cv.h>
// From http://stackoverflow.com/questions/2289690/opencv-how-to-rotate-iplimage
cv::Mat rotateImage(const cv::Mat& source, cv::Point2f center, double angle)
{
cv::Mat rot_mat = cv::getRotationMatrix2D(center, angle, 1.0);
cv::Mat dst;
cv::warpAffine(source, dst, rot_mat, source.size());
return dst;
}
int main()
{
cv::namedWindow("test1");
// Our rotated rect
int x = 300;
int y = 350;
int w = 200;
int h = 50;
float angle = 47;
cv::RotatedRect rect = cv::RotatedRect(cv::Point2f(x,y), cv::Size2f(w,h), angle);
// An empty image
cv::Mat img = cv::Mat(cv::Size(640, 480), CV_8UC3);
// Draw rotated rect as an ellipse to get some visual feedback
cv::ellipse(img, rect, cv::Scalar(255,0,0), -1);
// Rotate the image by rect.angle * -1
cv::Mat rotimg = rotateImage(img, rect.center, -1 * rect.angle);
// Set roi to the now unrotated rectangle
cv::Rect roi;
roi.x = rect.center.x - (rect.size.width / 2);
roi.y = rect.center.y - (rect.size.height / 2);
roi.width = rect.size.width;
roi.height = rect.size.height;
cv::imshow("test1", rotimg(roi));
cv::waitKey(0);
}