I've always wondered how I could get away with this:
int main(int argc, char **argv) {
printf("%p %s %d\n", &argv[1], argv[1], strlen(argv[1]));
char copy[strlen(argv[1]) + 1];
strcpy(copy, argv[1]);
printf("%p %s %d\n", ©, copy, strlen(copy));
return 0;
}
The char array copy
gets allocated anyway and the program runs fine, printing out the original and the copy. And Valgrind doesn’t complain about anything.
I thought dynamic arrays weren’t possible in C without malloc. Was I wrong?
This is a C99 feature and could be implemented on prior versions by the compiler.
Variable-length automatic arrays are allowed in ISO C99, and as an extension GCC accepts them in C90 mode and in C++. These arrays are declared like any other automatic arrays, but with a length that is not a constant expression. The storage is allocated at the point of declaration and deallocated when the brace-level is exited.