So I have written a function to determine how many factors a number has and list that number. However my function is not outputting the correct information.
def num_factors(integer):
result = 0
for i in range(1,integer+1):
if integer%i == 0:
result +=1
return result
print(num_factors(5))
print(num_factors(6))
print(num_factors(97))
print(num_factors(105))
print(num_factors(999))
For some reason it is outputting:
2
4
2
8
8
when it should be outputting:
0
2
0
6
6
With the line for i in range(1,integer+1): you are looping through all the numbers between 1 and your integer, including 1 and your integer, which are of course factors.
So for example if integer = 5, you'd loop over 1, 2, 3, 4, and 5. Out of these 1 and 5 are both of course factors of 5.
You could edit the line to for i in range(2,integer): to fix the error. The resulting code would look like this:
def num_factors(integer):
result = 0
for i in range(2,integer):
if integer%i == 0:
result +=1
return result
print(num_factors(5))
print(num_factors(6))
print(num_factors(97))
print(num_factors(105))
print(num_factors(999))
Though as someone in the comments suggested, you could reduce the search space even more.