Given that I have a column of values in the format
01.2020
12.2021
3.2019
02.2020
etc.
over a million rows or so, I want a VBA function to find the maximum value of the digits to the left of the period.
Something like
Option Explicit
Sub test()
Dim r As Range, c As Range
Dim max As Long, current As Long
Dim s As String
With År_2020
Set r = .Range(.Range("D2"), .Range("D" & .Rows.Count).End(xlUp))
End With
For Each c In r
current = CLng(Left(c, InStr(1, c, ".", vbBinaryCompare) - 1))
If current > max Then max = current
Next c
Debug.Print max
End Sub
works, but I feel like there ought to be a simpler solution.
Can someone please give some input on whether they can find a simpler solution?
=VALUE(LEFT(A1,FIND(".",A1)-1))
=MAX(B:B)
Dim ws As Worksheet
Set ws = ThisWorkbook.Worksheets("Sheet1")
Dim LastRow As Long 'find last used row
LastRow = ws.Cells(ws.Rows.Count, "A").End(xlUp).Row
Dim ValuesToConvert() As Variant 'read data into array
ValuesToConvert = ws.Range("A1", "A" & LastRow).Value 'will throw an error if there is only data in A1 but no data below, make sure to cover that case
Dim iVal As Variant
For iVal = LBound(ValuesToConvert) To UBound(ValuesToConvert)
'truncate after period (might need some error tests if period does not exist or cell is empty)
ValuesToConvert(iVal, 1) = CLng(Left(ValuesToConvert(iVal, 1), InStr(1, ValuesToConvert(iVal, 1), ".") - 1))
Next iVal
'get maximum of array values
Debug.Print Application.WorksheetFunction.Max(ValuesToConvert)