Getting a sublist using regex

Question

I have a list as such:

myList: ("ab";"bc";"cd","de");

I would like to get a sublist like that contains "b" I know i can do this:

myList like "*b*"

However this returns a binary list. 1100b; How can I return a list of ("ab";"bc") instead?

Answer 1

Following code returns needed sublist

myList: ("ab";"bc";"cd","de");
myList where myList like "*b*"

As you have mentioned

1. myList like "*b*" returns boolean list 1100
2. where 1100 returns list of indices with true value: 0, 1
3. myList 0 1 returns first two elements of myList