I asked a question about this earlier but may be over-complicating the issue. Given an array:
a = [3,4,3,6,3];
what code do I need to execute the following:
if the individual element of a == 3
then with a probability (p=0.67)
, change the value to 9
else leave the element as a 3
Thx. J
I guess this would be the shortest way to achieve what you want:
a[findall(x -> x==3 && rand()<=0.67, a)] .= 9