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javascriptphpweb-scrapinggoutte

Scrape <script> tag in PHP Goutte


I am scraping a website using PHP Goutte, but I need some informations that are indicated only in a script tag in the following way:

<script>
player.qualityselector({
        sources: [
          { format: 'auto', src: "xxx.example.com", type: 'video/mp4'},
                        { format: '1080p WEB-DL', src: "xxx.example.com", type: 'video/mp4'},
                          { format: '720p WEB-DL', src: "xxx.example.com", type: 'video/mp4'},
                          { format: '480p WEB-DL', src: "xxx.example.com4", type: 'video/mp4'},
                          { format: '360p WEB-DL', src: "xxx.example.com", type: 'video/mp4'},
                          { format: '240p WEB-DL', src: "xxx.example.com", type: 'video/mp4'},
      ],
      });
</script>

I need the src of each one, is that possible?


Solution

  • You can use regular expressions.

    Example

    $page_content = <<<EOF
    <script>
    player.qualityselector({
            sources: [
              { format: 'auto', src: "xxx.example.com", type: 'video/mp4'},
                            { format: '1080p WEB-DL', src: "xxx.example.com", type: 'video/mp4'},
                              { format: '720p WEB-DL', src: "xxx.example.com", type: 'video/mp4'},
                              { format: '480p WEB-DL', src: "xxx.example.com4", type: 'video/mp4'},
                              { format: '360p WEB-DL', src: "xxx.example.com", type: 'video/mp4'},
                              { format: '240p WEB-DL', src: "xxx.example.com", type: 'video/mp4'},
          ],
          });
    </script>
    EOF;
    
    preg_match_all('/src:\s"(.*)"/', $page_content, $match);
    $result = $match[1];
    print_r($result);
    

    Output

    Array
    (
        [0] => xxx.example.com
        [1] => xxx.example.com
        [2] => xxx.example.com
        [3] => xxx.example.com4
        [4] => xxx.example.com
        [5] => xxx.example.com
    )