get specific character

Question

I would like to remove Zero from a string, below is an example :

String a : 020200218-0PSS-0010

a.replaceall("-(?:.(?!-))+$", "**REPLACEMENT**")

Actual : 020200218-0PSS-0010 Expected : 020200218-0PSS-10

I'm using this regex to catch -0010 : -(?:.(?!-))+$

I just dont know what to do in the REPLACEMENT section to actually remove the unused zero (not the last zero for exemple "10" and not "1")

Thanks for reading!

Answer 1

You could use something like:

(?<=-)0+(?=[1-9]\d*$)

It translates to "find all zeros which come after a dash, leading up to a non-zero digit, followed by optional digits, till the end of the string."

The demo below is in PHP but it should be valid in Java as well.

https://regex101.com/r/7E2KKQ/1

$s.replaceAll("(?<=-)0+(?=[1-9]\d*$)", "")

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This would also work:

(?<=-)(?=\d+$)0+

Find a position in which behind me is a dash and ahead of me is nothing but digits till the end of the line. From this position match one or more continuous zeros.

https://regex101.com/r/cdTjOz/1