Answering a question in SO, I stumbled into this problem:
(def x [7 4 8 9 10 54 55 2 23 30 12 5])
(defn insert-x
([sorted-coll x]
(insert-x sorted-coll x
(if (= (type sorted-coll) clojure.lang.PersistentVector) [] '())))
([sorted-coll x acc]
(let [is-vector (= (type sorted-coll) clojure.lang.PersistentVector)
format-it #(into (if is-vector [] '()) %)
compare (if is-vector < >)]
(cond
(empty? sorted-coll) (format-it (cons x acc))
(compare (peek sorted-coll) x)
(format-it (concat
((if is-vector identity reverse) sorted-coll)
(conj acc x)))
:else (recur (pop sorted-coll) x (cons (peek sorted-coll) acc))))))
(defn bubble-sort [coll]
"Insert x into a sorted collection"
(reduce insert-x [] coll))
(bubble-sort x)
;; => [2 4 5 7 8 9 10 12 23 30 54 55]
The code does what it should.
However, insert-x
is not so elegant.
How to write insert-x
in a way that it is valid for all collections?
So that it is simpler/more elegant?
vectors should return vectors, lists should return lists etc.
i guess you're overthinking it.
you have two tasks:
first of all, i would rewrite the insert-x
like this for example:
(defn insert-x [sorted-coll x]
(let [[l r] (split-with #(<= % x) sorted-coll)]
`(~@l ~x ~@r)))
notice, it does more or less the same that your variant does: taking values until the desired positions, and then concatenating left and right parts with x
between them. notice also, it always produces properly sorted list, independent from the input type.
user> (insert-x [1 3 5 7 9] 10)
;;=> (1 3 5 7 9 10)
user> (insert-x [1 3 5 7 9] 0)
;;=> (0 1 3 5 7 9)
user> (insert-x [1 3 5 7 9] 4)
;;=> (1 3 4 5 7 9)
so, the next thing you need, is just to reduce input and return the properly typed result:
(defn my-sort [coll]
(let [sorted (reduce insert-x () coll)]
(if (vector? coll)
(vec sorted)
sorted)))
user> (my-sort '(0 3 1 4 2 5 10 7))
;;=> (0 1 2 3 4 5 7 10)
user> (my-sort [0 3 1 4 2 5 10 7])
;;=> [0 1 2 3 4 5 7 10]
user> (my-sort ())
;;=> ()
user> (my-sort [])
;;=> []