Is it somehow possible to easily mimic std::bind_front
in C++17 ? (just for member function wrapping is fine)
I took a look at implementation in c++20 aiming to copy but it seems its very much implementation specific indeed.
I'm thinking a lambda wrapper or template function/object might work?
(Performance is not an issue here)
This can be a starting point
template<typename F, typename ...FrontArgs>
struct bindfronthelper
{
bindfronthelper(F f, FrontArgs&&...args)
: mF{std::move(f)}
, mFrontArg{std::forward<FrontArgs>(args)...}
{}
template<typename ...BackArgs>
auto operator()(BackArgs&&...args) const
{
return std::apply(mF, std::tuple_cat(mFrontArg, std::forward_as_tuple(args...)));
}
F mF;
std::tuple<std::decay_t<FrontArgs>...> mFrontArg;
};
template<typename F, typename ...FrontArgs>
auto mybindfront(F f, FrontArgs&&...args)
{
return bindfronthelper<F, FrontArgs...>{std::move(f), std::forward<FrontArgs>(args)...};
}
Written quickly and not tested well, so there might be some pitfalls in corner cases. At least it shows how this can be achieved.
Ok I made this over complicated, here is simpler version:
template<typename T, typename ...Args>
auto tuple_append(T&& t, Args&&...args)
{
return std::tuple_cat(
std::forward<T>(t),
std::forward_as_tuple(args...)
);
}
template<typename F, typename ...FrontArgs>
decltype(auto) mybindfront(F&& f, FrontArgs&&...frontArgs)
{
return [f=std::forward<F>(f),
frontArgs = std::make_tuple(std::forward<FrontArgs>(frontArgs)...)]
(auto&&...backArgs)
{
return std::apply(
f,
tuple_append(
frontArgs,
std::forward<decltype(backArgs)>(backArgs)...));
};
}
still passes all test I've provided. I'm keeping old version since with a bit of work it can be tweaked to work with older standard of c++.