function pointer in C++ in bisection method

Question

I have a function my_func(), which takes 2 parameters a and b.

I want to define a function inside the solve_for_b_by_bisection() function, called f, such that I can just call f(b), which is my_func(a, b) for some fixed input a. How do I do that? Do I use a function pointer?

The reason I am doing this instead of calling f(a,b) directly is that in the actual thing I am working on, it has 10+ variables which are constants - it is not possible to repeat the variable list every time.

double my_func(const double a, const double b)
{
    /* some arbitary function */ 
}

double solve_for_b_for_contant_a_by_bisection (const double a, 
                                               const double upperbound, 
                                               const double lowerbound)
{
    double (*my_func_pointer)(const double b)
    {
        &my_func(a, b)
    }
             
    lowerboundvalue = *my_func(lowerbound)
    upperboundvalue = *my_func(upperbound)
    midpointvalue = *my_func(0.5 * (lowerbound+upperbound))
    /* The rest of the implementation */
}

Answer 1

You might use lambda:

auto func = [a](double b) { return my_func(a, b); };