Finding the Min of 3 Numbers with a Macro in x86 Assembly

Question

I've put together a simple macro that is meant to find the minimum of three numbers. In it's current state the macro will only work if the first or third parameter is the min, but not the second. Is there something off with my loops or comparisons that i'm not catching? Or anything I should be doing differently? Any recommendations or suggestions are appreciated.

findMin     MACRO   arg1, arg2, arg3
                
            mov eax, arg1 
            
            cmp eax, arg2         ; if eax is greater than arg2 swap
            jg swap1

            cmp eax, arg3         ; if eax is greater than arg3 swap
            jg swap2

            jmp endMac

            swap1: xchg eax, arg2
            swap2: xchg eax, arg3
            endMac:
          
            ENDM

Answer 1

Simplified Macro to Find the Min of 3 Numbers (Min will be in EAX register)

findMin    MACRO   arg1, arg2, arg3

           LOCAL L2, L3

           mov   eax, arg1
           
           cmp   eax, arg2
           jg    l2
           cmp   eax, arg3
           jg    l3
           jmp   endMac

           L2: xchg eax, arg2
               cmp  eax, arg3
               jg   L3
               jmp  endMac
           L3: xchg eax, arg3

           endMac:

           ENDM