I have a table with this data:
Date Value
...
2020-07-30 0.0
2020-07-31 12527.922
2020-08-01 29983.598
2020-08-02 34333.74
2020-08-03 33550.0
...
2020-08-30 22722.02
2020-08-31 21376.416
2020-09-01 23762.43
2020-09-02 16267.47
2020-09-03 25241.0
...
I need to sum from the first day of month to the next first day of month inclusive. Ie, from 2020-08-01 to 2020-09-01 inclusive and that value being in a column for all the days of the starting period (in this case 08) Any ideas? Thanks.
Expected output:
Date Value Period_Sum
...
2020-07-30 0 sum of 2020-07-01 to 2020-08-01
2020-07-31 1 ...
2020-08-01 2 sum of 2020-08-01 to 2020-09-01
2020-08-02 3 ...
2020-08-03 3 ...
...
2020-08-30 2 ...
2020-08-31 2 ...
2020-09-01 2 sum of 2020-09-01 to 2020-10-01
2020-09-02 1 ...
2020-09-03 2 ...
...
Base on Adrian's reply I'm trying to make it with sub selects like:
select
(
select
sum(qq.value)
from
data_table qq
where
qq.date between date_trunc('month', q.date)
and date_trunc('month', q.date) + interval '1 month'
) period_sum
, date
, value
from
data_table q
But it's missing the first day of the next month. I think I need to tweak the interval
part.
As example:
SELECT
SUM(VALUE)
FROM
some_table
WHERE
Date BETWEEN '2020-08-01' AND '2020-09-01';